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Examples of Triangle
- August 7, 2020
- Category: Examples of Triangle
(1) Calculate ABC and BAC.
Soln. ABC + 1000 = 1800 ( straight line ) ABC = 800
BAC = 1800 – ( 600 + 800 ) = 1800 – 1400 = 400
( sum of angles of a triangle = 180o )
(2) Calculate ACD and CDA.
Soln. ABC is isosceles ( AC = BC ) ABC = 400
ACD = ABC + BAC = 80o ( exterior angle )
CDA = 1800 – ( ACD + CAD ) = 1800 – ( 800 + 300 ) = 700
(3) ABCD is a quadrilateral where D = 70o, C = 80o. Bisectors of A and B meet at P. Calculate APB.
Soln. A + B = 3600 – ( 700 + 800 ) = 3600 – 1500 = 2100.
= 1050 APB = 1800 – 1050 = 750.
(4) AB = AD, BC = CD, BAD = 100o and DBC = 50o. Calculate ADC and BDC.
Soln. BCD is an isosceles triangle ( BC = CD )
BDC = 500
In ABD, AD = AB
ABD = ADB
Now, in ABD ,
ABD + ADB + BAD = 1800
2 ABD + 1000 = 1800
2 ABD = 800
ABD = 400 = ADB
ADC = ADB + BDC = 400 + 500 = 900.
(5) In a ABC, AB = 10, BC = 2, AC = 12. Find the length of median AD. If G is the centroid, find l ( GA ) and l ( GD ).
By Apollonius theorem, we have,
AB2 + AC2 = 2 AD2 + 2 BD2
102 + 122 = 2 AD2 + 2 ()2
244 – 194 = 2 AD2
50 = 2 AD2
AD = 5
G divides AD in the ratio 2 : 1, hence GA = AD = 5 =
and GD = 5 = .
Best of Luck…