Indefinite Integration

Parin Sir > Mathematical Proofs > Indefinite Integration

Feb

Pattern - 34 of Indefinite Integration

⋆ Pattern – 34

$I_n=\ \int x^n$ sin mx dx, then $I_... </p> <div class=$

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Feb

Pattern - 33 of Indefinite Integration

⋆ Pattern – 33

$I_n=\ \int x^n sin\ mx\ dx, then I_n$

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Tags: pattern, sabiti, maths, formula,

Feb

Pattern - 32 of Indefinite Integration

⋆ Pattern – 32

$I_n=\cos^n{x} dx$

$\therefore\ \ I_n=\ \int\cos^{n-1}{... </p> <div class=$

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Tags: maths, formula, pattern, sabiti,

Feb

Pattern - 31 of Indefinite Integration

⋆ Pattern – 31

$I_n=\ \int\sin^n{x}\ dx$ , then

$I_n=\ \frac{-\sin^{n-1}{x... </p> <div class=$

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Tags: formula, pattern, sabiti, maths,

Feb

Pattern - 30 of Indefinite Integration

⋆ Pattern – 30

$I_n=\ \int{\rm cosec}^n\ x\ dx, then$

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Tags: maths, proof, pattern, sabiti,

Feb

Pattern - 29 of Indefinite Integration

⋆ Pattern – 29

= ∫ $\sec^n{x} dx$ , then

$I_n=\ \frac{\tan{x\times \sec^{n-2}{x}}}{n... </p> <div class=$

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Feb

Pattern - 28 of Indefinite Integration

⋆ Pattern – 28

= ∫ $\cot^n{x} dx$ , then

$I_n=\ \frac{-\cot^{n-1\ }{x}}{x-1}-I_{n-2}\... </p> <div class=$

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Feb

Pattern - 27 of Indefinite Integration

⋆ Pattern – 27

If I_n = ∫ $\tan^n{x}$ dx, then

$I_n=\ \frac{\tan^{n-1\ }{x}}{n-1}-I_n-2\ ... </p> <div class=$

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Feb

Pattern - 26 of Indefinite Integration

⋆ Pattern – 26

$\int\frac{x^2+a}{x^4+bx^2+c\ }\ dx$

then divide numerator & denominator by & assume

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Feb

Pattern - 25 of Indefinite Integration

⋆ Pattern – 25

$\int\frac{ae^x+be^{-x}+n}{pe^x+qe^{-x}+r}\ dx$

where, a, b , n, p, q, r ∈ R then use

Posted in: Pattern - 25 of Indefinite Integration,

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