proof

Parin Sir > proof

Jun

Index

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Jun

Examples 7 to 9

(7) A shopkeeper borrowed Rs. 30000 from money lenders. For one loan he paid 10 % and for the other 15 % per annum. After one year, he paid Rs. 3600 as interest. How much did he borrow at each rate ?

Soln.

Posted in: Examples 7 to 9,

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Jun

Examples 4 to 6

(4) A certain sum amounts to Rs. 5800 in 2 years, Rs. 7400 in 6 years. Find the rate and the sum.

Soln. Here,

P + 6I = 7400
( Amount for 6 yrs. )

P + 2I = 5800

Posted in: Examples 4 to 6,

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Jun

Examples 1 to 3

(1) Find S. I. on Rs. 27000 at 7 $\frac{1}{3}$ % per annum for 3 years 8 months.

Soln. Here, P = 27000, R =

Posted in: Examples 1 to 3,

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Jun

Some important Formulas

☼ Some important Formulas :

$\large \mapsto$ A = P

e.g. Find the amount on Rs. 2000 f…

Posted in: Some important Formulas,

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Jun

Simple Interest

☼ Important Points On Simple Interest :

■ Principal ( or Sum or Capital ) : The money lent out or borrowed for a certain period is called the principal or the sum.

■ Interest :

Posted in: Simple Interest,

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14

Jun

Examples 16 to 20
(16) Successive discounts of 30% and 50% is equivalent to a single discount of how many per cent ?

Soln. Let M. P. = Rs.   100

$\therefore$ …

Posted in: Examples 16 to 20,

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14

Jun

Examplea 11 to 15
(11) If the selling price of 16 articles is the same as the cost price of 12 articles, find loss percent.

Soln. More sell   =   4 pencil. Instead of selling = 12 pencils

( for break–even point )

Instead of selling   …

Posted in: Examplea 11 to 15,

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14

Jun

Examples 6 to 10
(6) A man sells two houses for Rs. 256358 each. On one he gains 15 % and on the other he loses 15 %. Find his gain or loss per cent on the whole transaction.

Soln. In such a problem selling price is immaterial. There is always a …

Posted in: Examples 6 to 10,

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14

Jun

Examples 1 to 5
(1) Find gain or loss percent, when :

(i) C.P. = Rs. 12.00 and S.P. = Rs. 13.80.

(ii) C.P. = Rs. 8.00 and S.P. = Rs. 5.20

Soln. (i) Gain = RS. ( 13.80 – 12.00 ) = Rs.1.80…

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